a '95 Ford Escort engine delivers a whopping 83.6 hp of power (go Speed Racer!), how much time will it take for the engine to do 5.69 
105 J of work?
(Hint: Note that one horsepower, 1 hp, is equal to 746 watts.)
+330 a '95 Ford Escort engine delivers a whopping 83.6 hp of power (go Speed Racer!), how much time will it take for the engine to do 5.69 multiplied by 105 J of work?
(Hint: Note that one horsepower, 1 hp, is equal to 746 watts.)
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First note this:
A horsepower is a term used for power, and is a rate of energy used/produced in a unit of time (energy/unit time).
A Joule (J) is a term for energy, and is a quantity of energy equal to a watt-second. Its rate form is 1 joule per second equals 1 watt (1J/s = 1w) and 1 watt-second = 1 Joule (1Ws =1 J).
To solve this, convert horsepower to watts (power), then watts to joules per second (power), then divide the rate (power) by the requested amount of work (energy) and this will yield the time required (at that rate).
The default unit of time for power is 1 hour (3600 seconds).
83.6 hp * (746w/1hp) = 62365.6w (power)
62365.6w / (1 J/s) = 62365.6 J/s (power)
5.69 * 105J = 597.45J (energy, from question)
(597.45J) / (62365.6 J/s) = 0.009572s or 9.572ms (amount of time required)
(Note. Corrected error: original solution was inverted-- that means WRONG!).
~~D~~
+330 a '95 Ford Escort engine delivers a whopping 83.6 hp of power (go Speed Racer!), how much time will it take for the engine to do 5.69 multiplied by 105 J of work?
(Hint: Note that one horsepower, 1 hp, is equal to 746 watts.)
------------
First note this:
A horsepower is a term used for power, and is a rate of energy used/produced in a unit of time (energy/unit time).
A Joule (J) is a term for energy, and is a quantity of energy equal to a watt-second. Its rate form is 1 joule per second equals 1 watt (1J/s = 1w) and 1 watt-second = 1 Joule (1Ws =1 J).
To solve this, convert horsepower to watts (power), then watts to joules per second (power), then divide the rate (power) by the requested amount of work (energy) and this will yield the time required (at that rate).
The default unit of time for power is 1 hour (3600 seconds).
83.6 hp * (746w/1hp) = 62365.6w (power)
62365.6w / (1 J/s) = 62365.6 J/s (power)
5.69 * 105J = 597.45J (energy, from question)
(597.45J) / (62365.6 J/s) = 0.009572s or 9.572ms (amount of time required)
(Note. Corrected error: original solution was inverted-- that means WRONG!).
~~D~~
