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# Can anyone plz help me???

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How many bases \(b\) are there such that 663\(_b\) is prime?

Jun 30, 2019

#1
+1

Here is my "guess" (if I understand your question) !.

I don't think there is any base between 7 and 36 where 663 is prime. I couldn't find a single base between 7 and 36 where 663 is a prime number. Sorry, that is the best I could do.

Jun 30, 2019
#2
+1

How many bases b are there such that 663b is prime?

I don't think there are any.  663 is the same quantity, irrespective of what base you write it in, and that quantity is divisible.

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Jul 1, 2019
#3
+10

tommarvoloriddle  Jul 1, 2019
#4
+1

Base 2 can only have digits 0 and 1.  No base up to and including 6 can have the digit 6 - that's why Guest #1 started at base 7.

Alan  Jul 1, 2019
#5
+1

tommarvoloriddle, my answer works for base 2

in base 10  --           663      divided by    39     equals   17        therefore not prime

in base   2  --  1010010111 divided by 100111 equals 10001    therefore not prime

That's what i meant by 663 is the same quantity no matter what base you write it in.  My interpretation of the question was different from that of Guest #1.  On reflection, and especially Alan's and your comments, I now realize I was looking at it the wrong way.

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Guest Jul 1, 2019
#6
+3

The number 663b is   6b2 + 6b + 3  or  3(2b2 + 2b + 1)  which is the product of two integers (assuming b is an integer), hence cannot be prime for any base b.

Jul 1, 2019