+17 If 11 footballs and 4 baseballs cost $803 and 6 footballs and 6 baseballs cost $522, then how much does 1 football cost and how much does 1 baseball cost?
11f + 4 b = 803
6f + 6b = 522 multiply the entire first equation by - 1.5 then add it to the second equation which will
allow you to solve for 'f' easily.....use this value of 'f' in any of the equations to compute b...try it yourself
jujubies and smarties Q is similar
+284 So we have the following equations:
Equation 1: 11f + 4b = 803
and
Equation 2: 6f + 6b = 522.
If we take equation 2, we can simplify it into:
f + b = 87 (by dividing f, b, and 522 by 6.)
This gives us f = 87 - b.
We can substitute this value into equation 1 as shown:
11(87 - b) + 4b = 803
We then use the distributive property which gives us:
957 - 11b + 4b = 803
Combine like terms:
957 - 7b = 803
Simplify:
-7b = -154
Divide both sides by -7:
b = 22.
The question asks for the value of a baseball and a football so we substitute this into equation 2 which gives us:
6f + 6(22) = 522
6f + 132 = 522
6f = 390
f = 65.
Hope this helped!
Caffeine :)
