If 11 footballs and 4 baseballs cost $803 and 6 footballs and 6 baseballs cost $522, then how much does 1 football cost and how much does 1 baseball cost?

Owenmunslow Jan 18, 2021

#1**0 **

11f + 4 b = 803

6f + 6b = 522 multiply the entire first equation by - 1.5 then add it to the second equation which will

allow you to solve for 'f' easily.....use this value of 'f' in any of the equations to compute b...try it yourself

jujubies and smarties Q is similar

Guest Jan 18, 2021

#2**+2 **

So we have the following equations:

Equation 1: 11f + 4b = 803

and

Equation 2: 6f + 6b = 522.

If we take equation 2, we can simplify it into:

f + b = 87 (by dividing f, b, and 522 by 6.)

This gives us f = 87 - b.

We can substitute this value into equation 1 as shown:

11(87 - b) + 4b = 803

We then use the distributive property which gives us:

957 - 11b + 4b = 803

Combine like terms:

957 - 7b = 803

Simplify:

-7b = -154

Divide both sides by -7:

**b = 22.**

The question asks for the value of a baseball *and *a football so we substitute this into equation 2 which gives us:

6f + 6(22) = 522

6f + 132 = 522

6f = 390

**f = 65.**

Hope this helped!

Caffeine :)

Caffeine Jan 18, 2021