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# Can someone explain these two problems? I don't understand what it's saying.

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don't have to answer these, I just want to know what it means

1.I need to earn an A on my chemistry experiment. To earn an A, my observed value must be within a 5% error of the accept value. The accepted value for the density of aluminum is 2.699 g/ cubic cm. What is the lowest density that I can observe and still earn an A?

2. I need to earn an A on my chemistry experiment. To earn an A, my observed value must be within a 5% error of the accept value. The accepted value for the density of aluminum is 2.699 g/ cubic cm. What is the highest density that I can observe and still earn an A?

Jun 8, 2021

#1
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5%  of  2.699   =   .05 *  2.699   =  .13495

2.699   -  .13495  =

2.56405  g / cm^3

For the  greatest  observed density......add    2.699 + .13495

Jun 8, 2021
edited by CPhill  Jun 8, 2021
edited by CPhill  Jun 8, 2021
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thanks again, CPhill!

KindaFrisky  Jun 8, 2021
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NP !!!!

CPhill  Jun 8, 2021
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KF, you've posted 17 questions on this site and every single one of them has more than one question on it. I mean, just saying, this site isn't really for posting your homework and expecting people to do it for you. Just saying. Do the problems the best you can yourself first.

Jun 8, 2021