Can someone help △EDC is similar to △ABC. Solve for x.
△ABC is similar to △DEF.
△EDC is similar to △ABC , so side DC corresponds to side BC .
Let the scale factor from △EDC to △ABC be s .
DC * s = BC
4 * s = 6
s = 6/4
s = 1.5
So each side of △ABC is 1.5 times the corresponding side of △EDC.
△EDC is similar to △ABC , so side EC corresponds to side AC .
EC * 1.5 = AC
And we can see from the picture that EC = x and AC = 12.5 - x , so....
x * 1.5 = 12.5 - x
1.5x = 12.5 - x
Add x to both sides of the equation.
1.5x + x = 12.5
2.5x = 12.5
Divide both sides by 2.5 .
x = 5