Can someone help me on this?
I'm stuck
-3/10x - 2 < 2/5
and this
4 + 14b ≥ 13(b + 4)
-3/10x - 2 < 2/5
To get rid of fractions, multiply each term by 10: (10)(-3/10x) - (10)(2) < (10)(2/5_
---> -3x - 20 < 4
Add 20 to both sides: -3x < 24
Divide both sides by -3 x > -8
(When you multiply both sides of an inequality by a negative number, you must change the direction of the inequality sign; you don't do this when you multiply or divide by a positive number; and you don't do this when you add or subtract either a positive or negative number.)
4 + 14b ≥ 13(b + 4)
Use the Distributive Property:: 4 + 14b ≥ 13b + 52
Subtract 13b from both sides: 4 + b ≥ 52
Subtract 4 from both sides: b ≥ 48
-3/10x - 2 < 2/5 multiply through by 10 to clear the fractions
-3x - 20 < 4 add 20 to both sides
-3x < 24 divide by -3 (and remember to "reverse" the inequality sign)
x > -8
and this
4 + 14b ≥ 13(b + 4) simplify
4 + 14b ≥ 13b + 52 subtract 13b, 4 from each side
b ≥ 48
-3/10x - 2 < 2/5
To get rid of fractions, multiply each term by 10: (10)(-3/10x) - (10)(2) < (10)(2/5_
---> -3x - 20 < 4
Add 20 to both sides: -3x < 24
Divide both sides by -3 x > -8
(When you multiply both sides of an inequality by a negative number, you must change the direction of the inequality sign; you don't do this when you multiply or divide by a positive number; and you don't do this when you add or subtract either a positive or negative number.)
4 + 14b ≥ 13(b + 4)
Use the Distributive Property:: 4 + 14b ≥ 13b + 52
Subtract 13b from both sides: 4 + b ≥ 52
Subtract 4 from both sides: b ≥ 48