+595 Can someone help me with this?
y=-2+sin(3Ø)-π/3
Amplitude
Period
Verticle Shift
Y- intercept
y=2 tan(Ø)+1
Verticle Stretch
Period
Phase Shift
Verticle Shift
Y-intercept
+129845 y = - 2sin (3θ) -pi/3
Amplitude = l -2 l = 2
Period = the "3" indicates that there are 3 periods in 2pi....thus each period is 2pi/3 rads long
Verticle Shift = -pi/3 units down
Y- intercept.....to find this, set θ to 0 and we have :
y = -2 sin (3 * 0) - pi / 3
y = -2 sin (0) - pi / 3
y = 0 - pi/3
y = - pi/ 3 ⇒ y intercept
Here's the graph : https://www.desmos.com/calculator/er5ysgihkp
+775 Where can I get the θ (theta) symbol that looks like an O with a / through it? (The one that jbouyer used)
In \(\LaTeX\), it is \(θ\).
+129845 y = 2tan ( θ) + 1
Verticle Stretch - the "2" indicates that this graph is stretched by a factor of 2 from the normal tangent graph
Period - same period as the normal tangent graph......pi rads
Phase Shift - there is no phase shift
Verticle Shift - the "1" means it is shifted up one unit
Y-intercept....let θ = 0 and we have
y = 2 tan (0) + 1
y = 2(0) + 1
y = 1 ⇒ y intercept
Here's the graph : https://www.desmos.com/calculator/v5o9vci8rf
