+0  
 
0
48
3
avatar+593 

Can someone help me with this?

y=-2+sin(3Ø)-π/3

 

Amplitude

Period

Verticle Shift

Y- intercept

 

y=2 tan(Ø)+1

 

Verticle Stretch

Period

Phase Shift

Verticle Shift

Y-intercept

 Dec 17, 2018
 #1
avatar+94526 
+3

y = - 2sin (3θ) -pi/3   

 

Amplitude =  l -2 l   =  2

 

Period =  the "3" indicates that there are 3 periods in 2pi....thus each period is 2pi/3 rads long

 

Verticle Shift  =  -pi/3 units down 

 

Y- intercept.....to find this, set  θ to  0   and we have :

 

y = -2 sin (3 * 0)  - pi / 3

 

y =  -2 sin (0) - pi / 3

 

y = 0 - pi/3

 

y =  - pi/ 3  ⇒   y intercept

 

Here's the graph : https://www.desmos.com/calculator/er5ysgihkp

 

 

cool cool cool

 Dec 17, 2018
 #2
avatar+731 
0

Where can I get the θ (theta) symbol that looks like an O with a / through it? (The one that jbouyer used)

 

In \(\LaTeX\), it is \(θ\).

PartialMathematician  Dec 17, 2018
 #3
avatar+94526 
+3

y = 2tan ( θ) + 1

 

 

Verticle Stretch - the "2" indicates that this graph is stretched by a factor of 2 from the normal tangent graph

 

Period  -  same period as the normal tangent graph......pi rads

 

Phase Shift   -  there is no phase shift

 

Verticle Shift  - the "1"  means it is shifted up one unit

 

Y-intercept....let   θ  =  0    and we have

 

y = 2 tan (0) + 1

 

y =   2(0) + 1

 

y = 1   ⇒   y intercept

 

 

Here's the graph : https://www.desmos.com/calculator/v5o9vci8rf

 

cool cool cool

 Dec 17, 2018

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