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# Can someone help with this?

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I think I complete the square but idk Rewrite the expression \$4s^2 + 28s + 45\$ in the form \$(cs + p)^2 + q\$. What is \$q\$?

AnonymousConfusedGuy  Oct 20, 2017
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### 3+0 Answers

#1
+82811
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4s^2 + 28s + 45    factor out  the 4

4 [ s^2  + 7s  +  45/4]

Take (1/2) of 7  = 7/2......square this = 49/4  ....add it and subtract it

4 [ s^2 + 7s + 49/4 + 45/4 - 49/4 ]

Factor the first three terms and simplify

4 [  ( s + 7/2)^2  - 1 ]

4(s + 7/2)^2  - 4

So q =  -4

CPhill  Oct 20, 2017
#2
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CPhill: Aren't you actually dividing by 4 in the first step and it should disappear altogether in the 2nd step (outside the bracket)?

Guest Oct 20, 2017
#3
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This would be true if we were setting the equation to 0  and solving

But we aren't solving anything here......we are just completing the square

CPhill  Oct 20, 2017

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