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Given the area of a rectangle is A = bh, and assuming the rectangle is open on one side with a perimeter of b + 2h = 40, what formula will maximize the area of the rectangle?

A=20h−2h^2

 

A=40h−h^2

 

A=20h−h^2

 

A=40h−2h^2

 Dec 6, 2020

Best Answer 

 #2
avatar+1998 
+1

i didnt realize i was signed out as guest. but i think its D! (:

 Dec 6, 2020
edited by jjennylove  Dec 6, 2020
 #1
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+1

i think its D

 Dec 6, 2020
 #2
avatar+1998 
+1
Best Answer

i didnt realize i was signed out as guest. but i think its D! (:

jjennylove  Dec 6, 2020
edited by jjennylove  Dec 6, 2020
 #3
avatar+114090 
+1

Correct  !!!!

 

Good to see you, jenny   !!!!

 

 

cool cool cool

CPhill  Dec 6, 2020
 #4
avatar+1998 
+1

Awesome! this cal class has been tough.

 

Nice to see your back! I hope you have been well smiley

jjennylove  Dec 6, 2020
 #5
avatar+114090 
0

Been good.....just took a little "break"  ( for about  5 months....LOL!!!!)

 

cool cool cool

CPhill  Dec 6, 2020
 #6
avatar+1998 
+1

Hey! I really think you needed it, you've helped many all which are very appreciative of you. I have honeslty have been on a break from asking qustions lol! i really havent been on here much maybe once a month or so. I have been grasping this cal work pretty good, even though at times its a bit tough.cheeky

jjennylove  Dec 6, 2020

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