Given the area of a rectangle is A = bh, and assuming the rectangle is open on one side with a perimeter of b + 2h = 40, what formula will maximize the area of the rectangle?
A=20h−2h^2
A=40h−h^2
A=20h−h^2
A=40h−2h^2
+1995 i didnt realize i was signed out as guest. but i think its D! (:
+1995 Awesome! this cal class has been tough.
Nice to see your back! I hope you have been well 
+129852 Been good.....just took a little "break" ( for about 5 months....LOL!!!!)
+1995 Hey! I really think you needed it, you've helped many all which are very appreciative of you. I have honeslty have been on a break from asking qustions lol! i really havent been on here much maybe once a month or so. I have been grasping this cal work pretty good, even though at times its a bit tough.
