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# can someone help?

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Given the area of a rectangle is A = bh, and assuming the rectangle is open on one side with a perimeter of b + 2h = 40, what formula will maximize the area of the rectangle?

A=20h−2h^2

A=40h−h^2

A=20h−h^2

A=40h−2h^2

Dec 6, 2020

#2
+1998
+1

i didnt realize i was signed out as guest. but i think its D! (:

Dec 6, 2020
edited by jjennylove  Dec 6, 2020

#1
+1

i think its D

Dec 6, 2020
#2
+1998
+1

i didnt realize i was signed out as guest. but i think its D! (:

jjennylove  Dec 6, 2020
edited by jjennylove  Dec 6, 2020
#3
+114090
+1

Correct  !!!!

Good to see you, jenny   !!!!

CPhill  Dec 6, 2020
#4
+1998
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Awesome! this cal class has been tough.

Nice to see your back! I hope you have been well

jjennylove  Dec 6, 2020
#5
+114090
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Been good.....just took a little "break"  ( for about  5 months....LOL!!!!)

CPhill  Dec 6, 2020
#6
+1998
+1

Hey! I really think you needed it, you've helped many all which are very appreciative of you. I have honeslty have been on a break from asking qustions lol! i really havent been on here much maybe once a month or so. I have been grasping this cal work pretty good, even though at times its a bit tough.

jjennylove  Dec 6, 2020