If y=\(\frac{2x-3x^2}{3}\) and x=2a+1, what is the value of y when a=-1?
x=2a+1
= (2)(-1)+1
x = -1
y = [2(-1) - 3(-1)^2 ] / 3
= (-2 -3)/3
= -5/3
Thank you.
+37146 
