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If y=\(\frac{2x-3x^2}{3}\) and x=2a+1, what is the value of y when a=-1?

 Jun 12, 2021
 #1
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x=2a+1

  = (2)(-1)+1

x = -1

 

 

y = [2(-1) - 3(-1)^2 ] / 3

  =  (-2 -3)/3

  = -5/3

 Jun 12, 2021
 #2
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+1

Thank you.

Guest Jun 12, 2021

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