Solve the following systems by graphing on your calculator or a website and give the solution. Then show how the solutions would be verified, by using the LEFT SIDE = RIGHT SIDE method.
y=2x2+7x−5
y=−1/3x2−2x+9
+514 Well if ur solving for x, then 2x2 + 7x - 5 = -1/3x2 − 2x + 9
\(2x^3+7x-5=-\frac{1}{3}x^2-2x+9\)
\(=6x^3+21x-15=-x^2-6x+27\)
\(=6x^3+21x-42=-x^2-6x\)
\(=6x^3+27x-42=-x^2\)
\(=6x^3+x^2+27x-42=0\)
\(=x\approx \:1.15942\dots \)
+128475 See here : https://www.desmos.com/calculator/oe0gaxs2tt
The solutions are ( ≈ -5.046, ≈ 10.604) and ( ≈ 1.189, ≈ 6.151)
2x^2 + 7x - 5 = (-1/3)x^2 - 2x + 9 multiply through by 3
6x^2 + 21x - 15 = -x^2 - 6x + 27 rearrange as
7x^2 + 27x - 42 = 0
Use the quad formula to get
x = -27 ± sqrt [ 27^2 - 4 (7) ( -42) ]
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2 * 7
If you calculate this correctly you should get the solutions for x shown by the graph.....
