How do i prove csc2x+sec2x=csc2xsec2x?
I dont even know which identity to start with...
i know csc=1/sin
sec=1/cos
sin2+cos2=1
csc = 1/sin and sec = 1/cos so the left-hand side of the equality can be written as:
csc2x + sec2x = 1/sin2x + 1/cos2x
Collect over the common denominator obtained by multiplying sin2x and cos2x together and use the fact that cos2 + sin2 = 1 .
csc2x + sec2x = 1/sin2x + 1/cos2x = (cos2x + sin2x)/(sin2x*cos2x) = 1/(sin2x*cos2x) = csc2x*sec2x
The final expression is the same as the right-hand side of the original equality.
csc = 1/sin and sec = 1/cos so the left-hand side of the equality can be written as:
csc2x + sec2x = 1/sin2x + 1/cos2x
Collect over the common denominator obtained by multiplying sin2x and cos2x together and use the fact that cos2 + sin2 = 1 .
csc2x + sec2x = 1/sin2x + 1/cos2x = (cos2x + sin2x)/(sin2x*cos2x) = 1/(sin2x*cos2x) = csc2x*sec2x
The final expression is the same as the right-hand side of the original equality.