+0  
 
+2
1692
1
avatar+59 

never done this before can someone help me in a way that I will understand thanks.

 

A hotel is in the shape of a  cylinder, with a circular foundation. The circumference of the foundation is 5 times the radius, increased by 72.96 ft. Find the radius of the circular foundation. Use 3.14 as an approximation for

piπ.

 

The radius of the foundation is approximate  ___ ft, ft2,  ft3 , 

 Nov 29, 2017
 #1
avatar+128079 
+2

A hotel is in the shape of a  cylinder, with a circular foundation. The circumference of the foundation is 5 times the radius, increased by 72.96 ft. Find the radius of the circular foundation. Use 3.14 as an approximation for

piπ.

 

 

Circumference of the foundation is    5r + 72.96       (1)

 

And circumference is  given by    2 * 3.14 * r       (2)

 

Setting (1)  = (2)   we have that

 

5r  + 72.96   =  2 * 3.14 * r        simplify the right side

 

5r + 72.96  = 6.28 r          subtract 5r from  both sides

 

72.96  = 1.28r        divide both sides by  1.28

 

57  = r        [  i.e.....the radius is 57 ft  ]

 

 

cool cool cool

 Nov 29, 2017

2 Online Users

avatar