+505 How many arrangements of the numbers \(1, 2, 3, \dots, 7\) are there where the sum of any two adjacent numbers is odd?
Can someone start me off? I'll try to do the rest :)
+1224 There are a total of 5040 arrangements.
Keep these relationships in mind:
even + odd = odd
odd + even = odd
odd + odd = even
even + even = odd
To have an odd sum of two adjacent numbers, they must have opposite parity (one even, one odd).
If I'm entirely honest, this looks like an interesting problem to solve. Even I haven't figured it out yet! I hope this gets you started.
