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Can somoeone check if i am right?

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A ship leaves port at noon at a bearing of 293°.  The ship’s average rate of speed over this time is 18 miles per hour.

Describe the location of the ship at 3:30 p.m. by writing a vector in component form. Then explain what these components mean in terms of the scenario.

Drag a value into each box to correctly complete the statements.

Feb 10, 2021

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I think, that in sailing, a  bearing of  0°  is true North  and  the  bearing angle is  measured  clock-wise  from  this position

A bearing of 293° ( trigonometrically  speaking)  corresponds   to   an angle of 360  - 293  -90   =157°

{Note  that a bearing of 270°  =  180°  in  trigonometric terms.....so  180  - 23 =  157° }

In 3 1/2 hours....the  ship   has traveled 63 miles

So.....its   position in the  coordinate plane =  (  63 cos 157° . 63 sin 157°) = (-58  , 24.6)

So   it is   58  miles west   and  24.6 miles north of its  original position

See the image  here , lovesosa12  :

A is the starting point   and B is the  ending point

Feb 10, 2021