+296 A ship leaves port at noon at a bearing of 293°. The ship’s average rate of speed over this time is 18 miles per hour.
Describe the location of the ship at 3:30 p.m. by writing a vector in component form. Then explain what these components mean in terms of the scenario.
Drag a value into each box to correctly complete the statements.
+128474 I think, that in sailing, a bearing of 0° is true North and the bearing angle is measured clock-wise from this position
A bearing of 293° ( trigonometrically speaking) corresponds to an angle of 360 - 293 -90 =157°
{Note that a bearing of 270° = 180° in trigonometric terms.....so 180 - 23 = 157° }
In 3 1/2 hours....the ship has traveled 63 miles
So.....its position in the coordinate plane = ( 63 cos 157° . 63 sin 157°) = (-58 , 24.6)
So it is 58 miles west and 24.6 miles north of its original position
See the image here , lovesosa12 :
A is the starting point and B is the ending point
