can you find 5 more pythagorean triples

This is easy  !!!!

3 - 4 - 5     is one.......and all multiples of this relationship are triples...so

6 - 8 -10     [multiply the basic one by 2]

9 -12- 15    [ by 3]

12 - 16 - 20  [by 4]

15 - 20 - 25   [by 5]

18 - 24 - 30   [by 6]

Pythagorean triples can be generated by the expressions

m^2 - n^2,     2mn,     m^2 + n^2

since

(m^2 - n^2)^2   +   (2mn)^2

=  m^4 - 2(m^2)(n^2) + n^4 + 4(m^2)(n^2) = m^4 + 2(m^2)(n^2) + n^4

=   (m^2 + n^2)^2.

You can choose any integer values for m and n, providing that n > 0 and m > n.

For example, m = 2 and n = 1 gets you the well known 3, 4, 5 case.

m = 5, n = 2 produces 21, 20, 29, (check 21^2 + 20 ^2 = 441 + 400 = 841 = 29^2), etc.

An infinite number of possibilities.

- Bertie

Another common one that is sometimes seen in construction etc    is  5  12  13    and all of the multiples of....

That's m = 3, n=2.

Yep, it is....

  was just pointing to a triangle worth committing to memory.... (along with 3 4 5 )