CAN YOU HELP ME WITH A EQUATION? its the square root of 79 minus 5X equals X minus 11
I will solve both situations given by hectictar.
Situation 1:
\(\sqrt{79}-5x = x-11\\ 6x = \sqrt{79} + 11\\ x = \dfrac{\sqrt{79}+11}{6}\)
Situation 2:
\(\sqrt{79-5x}=x-11\\ 79-5x = x^2 -22x+121\\ x^2-17x+42=0\\ (x-14)(x-3) = 0\\ x = 14\text{ OR }3\)