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# cardinal number

0
359
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whats the cardinal number for 101, 102, 103, 104, . . . 128 and 101, 103, 105, . . . 251

Guest Sep 8, 2017
#1
+2139
0

The cardinal number of a set is actually a simple concept: it specifies how many there exists.

To find the set, just subtract the highest and lowest numbers. $$128-101=27$$

We do the exact same thing for the second set. $$251-101=140$$

TheXSquaredFactor  Sep 8, 2017
#2
0

27 is wrong

Guest Sep 8, 2017
#5
+92888
+1

Say you wanted the cardingal number of    101,102

you can see that it is 2 because there are 2 elements.

but 102-101=1   so that is why you have to add 1   :)

Melody  Sep 8, 2017
#3
+1126
+3

The Cardinal number of a finite set is the number of elements in the set.

If the set is sequential, then subtract the lowest from the highest and add 1

Example:

{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

10 - 1 =9

9 + 1 =10

Cardinal number is 10

GingerAle  Sep 8, 2017
#4
+19824
+1

whats the cardinal number for 101, 102, 103, 104, . . . 128 and 101, 103, 105, . . . 251

The number of distinct elements in a finite set is called its cardinal number.

It is denoted as n(A) and read as ‘the number of elements of the set’.

For example:

(i) Set A = {2, 4, 5, 9, 15} has 5 elements.

Therefore, the cardinal number of set A = 5. So, it is denoted as n(A) = 5.

Set A = {  101, 102, 103, 104, . . . 128  }

subtract from each element 100 we have 1, 2, 3, ... , 28

n(A) = 128-100 = 28

Set B = {  101, 103, 105, . . . 251  }

subtract from each element 100 we have 1, 3, 5, ... , 151

151 = 2n-1

so $$n = \frac{150}{2} = 75$$

n(B) = 75

heureka  Sep 8, 2017
edited by heureka  Sep 8, 2017