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I think I did the first one correct but I want to make sure because I was confused at first. I also need help with the last question. Please help. Thanks!

 Jan 17, 2019
 #1
avatar+23494 
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First one:   In 2.5 secs , the ball goes from 0 to 25 feet in height     25ft/2,5sec = 10ft/sec

Second one:

 

  in two minutes, pat goes from 0 to 125 yds      125yds/2min = 62.5 yds/min

                         cable car from 0 to 100 yds      100yds/2min = 50 yds/min

 

I think you can now do the others!cheeky

 Jan 17, 2019
 #3
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Thank you very much for your help! I was a little confused but it makes sense now.

Guest Jan 17, 2019
 #2
avatar+111357 
+2

Note that.....on the last one.......the graph of the cable car is a straight line....thus it's average rate of change is constant = 50 yd / min

 

From 2 - 4 min  ....the avg rate of change  for Pat is  [200 - 125 ] / 2 =  75 / 2  =  37.5 yds / min

 

From 4 - 5 min.....the avg rate of change for Pat is  [225 - 200] / 2  =  25 / 2  =   12.5 yds / min

 

Note that Pat is getting tired......but the cable car isn't.....LOL!!!!

 

 

cool cool cool

 Jan 17, 2019
 #4
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Thank you so much for helping! I understand it much better now.

Guest Jan 17, 2019

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