I think I did the first one correct but I want to make sure because I was confused at first. I also need help with the last question. Please help. Thanks!

Guest Jan 17, 2019

#1**+1 **

First one: In 2.5 secs , the ball goes from 0 to 25 feet in height 25ft/2,5sec = 10ft/sec

Second one:

in two minutes, pat goes from 0 to 125 yds 125yds/2min = 62.5 yds/min

cable car from 0 to 100 yds 100yds/2min = 50 yds/min

I think you can now do the others!

ElectricPavlov Jan 17, 2019

#2**+2 **

Note that.....on the last one.......the graph of the cable car is a straight line....thus it's average rate of change is constant = 50 yd / min

From 2 - 4 min ....the avg rate of change for Pat is [200 - 125 ] / 2 = 75 / 2 = 37.5 yds / min

From 4 - 5 min.....the avg rate of change for Pat is [225 - 200] / 2 = 25 / 2 = 12.5 yds / min

Note that Pat is getting tired......but the cable car isn't.....LOL!!!!

CPhill Jan 17, 2019