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question 1)

 Mar 18, 2020
 #1
avatar+111360 
+2

We  can use  the Law of Cosines to  find the measure of the smaller angle...we have that

 

2.9^2  = 4^2 + 4^2  - 2 (4 * 4)  cos  (smaller angle in the rhombus)

 

Simplify

 

[ 2.9^2  -4^2 - 4^2 ]  /  [-2 (4 * 4)]  = cos (smaller angle in the rhombus)

 

Using the arccos  we  have  that

 

arccos ( [ 2.9^2  -4^2 - 4^2 ]  /  [-2 (4 * 4)] )  =  smaller angle in the rhombus ≈  42.51°

 

The larger angle in the rhombus  will be supplemental to this = 137.49°  = 137.5°

 

LOOKS LIKE YER ON A ROLL  !!!

 

 

cool cool cool

 Mar 18, 2020
 #2
avatar+1898 
+1

im really happy im understanding these! thank you so much your explaination !

jjennylove  Mar 18, 2020
 #3
avatar+682 
+2

Let rhombus side be       c = 4

1/2 of short diagonal       a = 1.45

1/2 of long  diagonal        b = ?

We have the right triangle  

Larger angle  β = ?                    cos(β/2) = a / c =68.74619°

                                                              β = 137.4923816°     indecision

IT IS TOTALLY______

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                                   V

 Mar 18, 2020
edited by Guest  Mar 18, 2020
edited by Guest  Mar 18, 2020
edited by Guest  Mar 18, 2020

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