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check my answers?

 Apr 17, 2020
 #1
avatar+483 
+2

secant = 1/cos

Dividing by -sqrt3 on both sides

\(\sec{\theta} = -\frac2{\sqrt3}\)

Rationalizing the denominator by multiplying it by sqrt3/sqrt3(which is one):

\(\sec{\theta} = -2\sqrt{3}/3\)

Substituting in 1/cos:

\(1/\cos{\theta} = -2\sqrt{3}/3\)

\(\cos{\theta} = -3/2\sqrt{3}\)

Rationalizing like before by multiplying by sqrt3 / sqrt 3, we get:

\(\cos{\theta} = -3\sqrt{3}/6 = -\sqrt3/2\)

The values for which this is true between [0, 2pi] are :

\(\cos{5\pi/6}\) radians (cos 150 degrees) and \(\cos{7\pi/6} \)(cos 210 degrees). The general forms for these are then indeed your answer because the period of cosine is 2pi.

 Apr 17, 2020
 #2
avatar+1898 
+1

thank you for your help! (: the explanation has helped

jjennylove  Apr 17, 2020

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