+327 Original Question:
1. Rectangle 1 has length x and width y. Rectangle 2 is made by multiplying each dimension of Rectangle 1 by a factor of k, where k > 0.
(a) Are Rectangle 1 and Rectangle 2 similar? Why or why not?
(b) Write a paragraph proof to show that the perimeter of Rectangle 2 is k times the perimeter of Rectangle 1.
(c) Write a paragraph proof to show that the area of Rectangle 2 is k^2 times the area of Rectangle 1.
Answers for (b) and (c):
(b):
(b) The perimeter of the rectangle is the sum of the measurements of all sides. Rectangle 1 should be, 2(W+L)=2(x+y). Rectangle 2 should be, 2(W+L)=2(2x+2y)=2(2(x+y)=4(x+y)=2[2(x+y)]. Which then simplifies to 2 times the perimeter of Rectangle 1.
(c) The area of a rectangle is the product of the lengths of two sides. To find Rectangle 1’s area you would multiply (x)(y). For Rectangle 2 the area formula would be (kx)(ky)=k^2*xy. Which would make Rectangle 2 k^2 times the area of Rectangle 1.
My other paragraph proof for (b) was...But didn't know if it as correct.:
The perimeter of the rectangle is the sum of the measurements of all sides. Rectangle 1 should be, Perimeter(Recangle 1)=2x+2y. Rectangle 2 should be, Perimeter(Recangle 2)=2kx+2ky. Which then simplifies to 2 times the k(2x+2y)=k(Perimeter of Rectangle 1).
Thank You!
+9479 On your first paragraph proof for (b) , you said, "Rectangle 2 should be, 2(W+L)=2(2x+2y)"
....Where did you get that the width and length of Rectangle 2 are 2x and 2y ?
Rectangle 1 has length x and width y .
Rectangle 2 has a length kx and a width ky .
Perimeter of Rectangle 1 = x + x + y + y
Perimeter of Rectangle 2 = kx + kx + ky + ky = k(x + x + y + y) = k( Perimeter of Rectangle 1 )
Your second paragraph proof for (b) is correct. 
And your paragraph proof for (c) is also correct.
Area of Rectangle 1 = xy
Area of Rectangle 2 = (kx)(ky) = k*x*k*y = k*k*x*y = k2(xy) = k2( Area of Rectangle 1 )
+129852 Thanks, hectictar.....here's my input.....
C looks good except for the last part.....it should be this :
" For Rectangle 2 the area formula would be (kx)(ky)=k^2*xy. Which would make Rectangle k^2 times the area of Rectangle 1. "
[We don't need the "2" ]
For B....consider this
The perimeter of the original rectangle = ( 2x + 2y) . And the sides of the "new rectangle" are kx and ky. So its perimeter is 2 (kx) + 2(ky) = k (2x + 2y) = "k" times the perimeter of the first.
Hope that helps !!!!
