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avatar+956 

Okay so first I did the cross product and I got: (3,8,1) 

Then I did: √(3)^2+(8)^2+(1)^2 

I get: √74 

Now the unit vector that's perpendicular to both is: 

(1/√74, 8/√74, 1/√74) 

 

Did I do it correctly?

Julius  May 16, 2018
 #1
avatar+91378 
+2

You computed the cross-product correctly, Julius

 

Also  the  √74  is correct

 

The  unit   vector   is

 

[1 / √74  ]  ( 3, 8 , 1)   =  

 

(3 / √74  ,   8 / √74 , 1 / √74  )

 

 

cool cool cool

CPhill  May 16, 2018
 #2
avatar+956 
+1

Oh, yes that's what I meant. Tysm!

Julius  May 16, 2018

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