Okay so first I did the cross product and I got: (3,8,1)
Then I did: √(3)^2+(8)^2+(1)^2
I get: √74
Now the unit vector that's perpendicular to both is:
(1/√74, 8/√74, 1/√74)
Did I do it correctly?
You computed the cross-product correctly, Julius
Also the √74 is correct
The unit vector is
[1 / √74 ] ( 3, 8 , 1) =
(3 / √74 , 8 / √74 , 1 / √74 )
Oh, yes that's what I meant. Tysm!
+956 
