Here ive got another question for you all to answer and help me!
The lenth of a rectangle is twice its breadth.If its perimeter is 108 cm, find the lenth and breadth of a rectangle.
Please can you explain its answer nicely!I solved this question but i got stuck in a step!so i want to see how it would be totally solved!
Let the breadth be B. Then, since the length is twice the breadth, call the length 28. And the perimeter of any rectangle is given by P = 2(W + L) where W is the width (breadth) and L is the length. So we have:
108 = 2(B + 2B) Divide by 2
54 = B + 2B Simplify on the right
54 = 3B Divide by 3
18 = B And that's the width (breadth) And the length is twice that = 2(18) = 36
Check that 36 + 36 + 18 + 18 = 108 .....Yep !!!!
Let the breadth be B. Then, since the length is twice the breadth, call the length 28. And the perimeter of any rectangle is given by P = 2(W + L) where W is the width (breadth) and L is the length. So we have:
108 = 2(B + 2B) Divide by 2
54 = B + 2B Simplify on the right
54 = 3B Divide by 3
18 = B And that's the width (breadth) And the length is twice that = 2(18) = 36
Check that 36 + 36 + 18 + 18 = 108 .....Yep !!!!
OOOHHH!NOOO!
What a SILLY ,mistake i made!
i thought the perimeter would be lxb instead of 2(l+b)!i thought hard but still the answer in my mind came lxb!Oh no what did i do!why do i always get confused in the perimeter and area of a rectangle! Now i have lost two marks , thats soo sad!is there any way to remember them both corectly CPhill?
Now i'll never make such a mistake!
BTW thank you for the answer!thumbs up from me!
Think of it this way, rosala......"perimeter" is how far you travel if you walk "around" something.......
So the "perimeter" of a rectangle is just the sum of its sides.....namely W + W + L + L = 2W + 2L = 2(W + L)
Think of "area" as a rug covering something.....in this case, a rectangle!!! And the area is just L X W...........
Does that help???