N2(g) + 3H2(g) → 2NH3(g)
This is the Free Energy measured under standard conditions, when the reaction is started with 1.0 M of each of the three gases present. Calculate the non-standard Free Energy change (∆G) at 298 K, given the following non-standard initial concentrations of the three gases. Answer in kJ.
∆Gfo = -16.6 kJ/mol for NH3 (g) at 298 K
initial concentration (M)
N21.0
H20.01
NH33
Δ G =
