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# Chemestry assistance

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You have 3.27 × 10^25 molecules of water. Find the volume of this in milliliters. Water has a molar mass of 18.01528 grams per mole and a density of 1 gram per milliliter. Avogadro's number is always 6.022 × 10^23 molecules per mole. Round to two decimal places.

This question has baffled me for a bit, i know i am supposed to chain these conversions together but I just can not seem to make it work for this type of question.

Jun 11, 2020

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Convert from molecules into milliliters:
3.27*10^25 molecules of[H, 2]O (water)

Divide the number of moles by AN to convert to moles:
(3.27*10^25 molecules)/1 * (1 mol)/(6.022*10^23 molecules) == 54.3 mol

The amount-of-substance, n, is:
n == 54.3 mol

m == n M == (54.3 mol)/1 * (18.01528 g)/(1 mol) == 978.21 g

Convert from grams to cubic centimeters using the relation 1 (cm)^3  (cubic centimeter) == 1 mL  (milliliter)[] and the density 1 g/(cm)^3  (gram per cubic centimeter) at STP of [H, 2]O:
(978.21 g)/1 * (1 (cm)^3)/(1 g) == 978.21 (cm)^3

Convert to milliliters using the relation 1 (cm)^3  (cubic centimeter) == 1 mL  (milliliter):
(978.21 (cm)^3)/1 * (1 mL)/(1 (cm)^3) == 978.21 mL

Jun 11, 2020