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avatar+870 

Complete the following Chemical equations:

(Of course, the amount of matter before and after the reaction must be the same;

If you don't know what it means, this means that there must be the same number of occurences of each element en each side of the arrow.

E.G.:

1C + 1O 2 1CO 2
 
Here there are still the same number of atoms of each element on each side:
There is one atom of carbon and two atoms of oxygen before and after the reaction.
Please note that the number before the symbol of the element is called a
stoichiometric factor
That's the only thing I want you to change in the exercices below!
The number written subscript behind the symbol of the element corresponds to the number of atoms of this element in the molecule. The stoichiometric factor corresponds to the number of occurences of this molecule. To get the number of atoms, you have to multiply those numbers together.
e.g.: 3O2
3×2=6, so there are 6 atoms of oxygen here.
Those two numbers always are positive integers.
 
Now it's your turn !)
 
For each equation, find the correct stoichiometric factors.
 
  1. _C + _O→ _CO
  2. _CO + _O2 → _CO2
  3. _Fe + _O2 → _Fe3O4
  4. _C4H10 + _O2 → _CO2 + _H2O
  5. _CH4 + _H2O → _CO + _H2
  6. _Zn + _O2 → _ZnO
  7. _Al + _O2 → _Al2O3
  8. _Cu + _O2 → _CuO
  9. _Cu + _O2 → _Cu2O
  10. _Cu2O + _O2 → _CuO

 

Good luck !    

 Jul 13, 2015

Best Answer 

 #1
avatar+33616 
+5

I'm not sure if you really want to know or if you've set it as a puzzle! Either way:

 

 Balanced chemical equations:

.

 Jul 14, 2015
 #1
avatar+33616 
+5
Best Answer

I'm not sure if you really want to know or if you've set it as a puzzle! Either way:

 

 Balanced chemical equations:

.

Alan Jul 14, 2015
 #2
avatar+870 
0

 

This is just some "brain food" as Melody said.

Anyway, your answers are perfect.

20/20

Here's your cookie:

 Jul 14, 2015
 #3
avatar+405 
+5

Yum?

 Dec 10, 2015

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