You have a box of chocolates that contains 54 pieces of which 31 are solid chocolate, 19 are filled with cashews, and 4 are filled with cherries. All the candies look exactly alike. You select a piece, eat it, select a second piece, eat it, and finally eat one last piece. Find the probability of selecting a solid chocolate piece followed by two cherry-filled chocolates.
+80 \(\frac{31}{52}*\frac{4}{51}*\frac{3}{50}=\frac{31}{11050}\)
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