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ONLY QUESTION C AND D PLEASE

for a: (3,-1) for B: (x-3)^2 + (y+1)^2 = 225

 Jan 8, 2019
 #1
avatar+98154 
+3

Here's a diagram : 

 

 

c)  If we draw a radius bisecting chord  PR.....it will meet PR at right angles......let E be the intersection of this radial line and  the chord

 

Triangle AEP is right  with  AP = 15, PE = 10

So.....AE is the distance from A  to PR.......and by the Pythagorean Theorem

 

AE =  √[ AP^2 - AE^2] = √ [ 15^2 - 10^2 ]  = √  [ 225 - 100]  = √125  =  5√5 units

 

d) Angle APR = angle APE 

And we can find the measure of angle APE as

 

cos APE = PE / AP =  10 / 15  =  2 /3

So

arccos (2/3)  = 48.189°

 

And angle APR = angle QPR......but angle RAQ  =  twice the measure of angle APE = 2 * 48.189 ≈ 96.4°  

 

But...in triangle RAQ, AR = AQ.....so angle ARQ = angle AQR

 

Angle ARQ can be found as   [ 180 - angle RAQ] / 2 =  [ 180 - 96.4 ] / 2 ≈  41.8°

 

 

cool cool cool

 Jan 8, 2019
 #3
avatar+777 
+1

ah thank you very much

YEEEEEET  Jan 10, 2019
 #2
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YA YEEET

 Jan 10, 2019

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