+0

# Circle and angle

+1
329
3
+845

ONLY QUESTION C AND D PLEASE

for a: (3,-1) for B: (x-3)^2 + (y+1)^2 = 225

Jan 8, 2019

#1
+111357
+3

Here's a diagram :

c)  If we draw a radius bisecting chord  PR.....it will meet PR at right angles......let E be the intersection of this radial line and  the chord

Triangle AEP is right  with  AP = 15, PE = 10

So.....AE is the distance from A  to PR.......and by the Pythagorean Theorem

AE =  √[ AP^2 - AE^2] = √ [ 15^2 - 10^2 ]  = √  [ 225 - 100]  = √125  =  5√5 units

d) Angle APR = angle APE

And we can find the measure of angle APE as

cos APE = PE / AP =  10 / 15  =  2 /3

So

arccos (2/3)  = 48.189°

And angle APR = angle QPR......but angle RAQ  =  twice the measure of angle APE = 2 * 48.189 ≈ 96.4°

But...in triangle RAQ, AR = AQ.....so angle ARQ = angle AQR

Angle ARQ can be found as   [ 180 - angle RAQ] / 2 =  [ 180 - 96.4 ] / 2 ≈  41.8°

Jan 8, 2019
#3
+845
+1

ah thank you very much

YEEEEEET  Jan 10, 2019
#2
0

YA YEEET

Jan 10, 2019