ONLY QUESTION C AND D PLEASE

for a: (3,-1) for B: (x-3)^2 + (y+1)^2 = 225

YEEEEEET Jan 8, 2019

#1**+3 **

Here's a diagram :

c) If we draw a radius bisecting chord PR.....it will meet PR at right angles......let E be the intersection of this radial line and the chord

Triangle AEP is right with AP = 15, PE = 10

So.....AE is the distance from A to PR.......and by the Pythagorean Theorem

AE = √[ AP^2 - AE^2] = √ [ 15^2 - 10^2 ] = √ [ 225 - 100] = √125 = 5√5 units

d) Angle APR = angle APE

And we can find the measure of angle APE as

cos APE = PE / AP = 10 / 15 = 2 /3

So

arccos (2/3) = 48.189°

And angle APR = angle QPR......but angle RAQ = twice the measure of angle APE = 2 * 48.189 ≈ 96.4°

But...in triangle RAQ, AR = AQ.....so angle ARQ = angle AQR

Angle ARQ can be found as [ 180 - angle RAQ] / 2 = [ 180 - 96.4 ] / 2 ≈ 41.8°

CPhill Jan 8, 2019