We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

ONLY QUESTION C AND D PLEASE

for a: (3,-1) for B: (x-3)^2 + (y+1)^2 = 225

YEEEEEET Jan 8, 2019

#1**+3 **

Here's a diagram :

c) If we draw a radius bisecting chord PR.....it will meet PR at right angles......let E be the intersection of this radial line and the chord

Triangle AEP is right with AP = 15, PE = 10

So.....AE is the distance from A to PR.......and by the Pythagorean Theorem

AE = √[ AP^2 - AE^2] = √ [ 15^2 - 10^2 ] = √ [ 225 - 100] = √125 = 5√5 units

d) Angle APR = angle APE

And we can find the measure of angle APE as

cos APE = PE / AP = 10 / 15 = 2 /3

So

arccos (2/3) = 48.189°

And angle APR = angle QPR......but angle RAQ = twice the measure of angle APE = 2 * 48.189 ≈ 96.4°

But...in triangle RAQ, AR = AQ.....so angle ARQ = angle AQR

Angle ARQ can be found as [ 180 - angle RAQ] / 2 = [ 180 - 96.4 ] / 2 ≈ 41.8°

CPhill Jan 8, 2019