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A running track is the ring formed by two concentric circles. If the circumferences of the two circles differ by 10 pi feet, how wide is the track in feet?

 

Thanks

AnonymousConfusedGuy  Apr 11, 2018
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3+0 Answers

 #1
avatar+85726 
+1

Note that if  the circumference of the larger circle is 10pi feet more....the track must be 5 feet wide

 

Proof....let the  radius of the smaller circle  = r

Then....let the radius of the larger circle be  r + 5

 

So.... circumference of the smaller circle is  2pi * r

And the circumference of the larger circle  is  2pi ( r + 5)  = 2pi * r +  10pi

 

Subtracting the smaller circumference from the larger, we get

 

[ 2 pi * r  + 10 pi ]  - [ 2 pi * r ]  =    10pi

 

 

cool cool cool

CPhill  Apr 11, 2018
 #2
avatar+85726 
+1

Here's a more formal way to do this, ACG

 

Let  the radius of the smaller circle  = R

Then the radius of the larger circle is just the radius of the smaller circle plus the width of the track, W

 

So

 

The circumference of the smaller circle plus 10pi ft  = the circumference of the larger circle

 

So we have

 

2pi(R) + 10pi   =  2pi (R + W)

 

2pi (R) + 10 pi  =  2pi (R)  + 2pi(W)        subtract 2pi (R) from  both sides

 

10 pi  = 2pi (W)

 

10  = 2W

 

5 (feet)  = W   = width of the track

 

 

cool cool cool

CPhill  Apr 12, 2018
 #3
avatar+925 
+1

Thank you!

AnonymousConfusedGuy  Apr 12, 2018

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