Circle O is tangent to AB at A, and angle ABD = 90 degrees. If AB = 12 and CD = 20, find the radius of the circle.
+2666 Let point E be the midpoint of CD.
Now, \(DE = EC =10\).
We know that \(AB = OE = 12\)
Applying the Pythagorean Theorem to \(\triangle OEC\), we find the hypotenuse, or in this case, the radius to be \(\color{brown}\boxed{2 \sqrt{61}}\)
+2666 Let point E be the midpoint of CD.
Now, \(DE = EC =10\).
We know that \(AB = OE = 12\)
Applying the Pythagorean Theorem to \(\triangle OEC\), we find the hypotenuse, or in this case, the radius to be \(\color{brown}\boxed{2 \sqrt{61}}\)
