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avatar+51 

Please help.

 May 9, 2018
 #1
avatar+94619 
+2

Since  OX  meets chord MN at right angles, it bisects MN....so   XN  =  6

 

And  OY meets chord PQ at right angles, so it bisects PQ.

 

And since OX  = OY....chords  MH  and PQ are equidistant  from the center of the circle. And chords that are equidistant from the center of a circle have the same length.

 

So PQ  = 12.....so YQ  =  6

 

 

 

cool cool cool

 May 9, 2018
 #2
avatar+51 
+1

Thanks Again.

melvsky  May 9, 2018

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