I don't think that I am setting the last one up correctly. Each time I try solving it, I get a negative answer. The others I'm confused on. Please help. Thanks!
The last one: the two angles encompass the entire circle 3600
remember, inscribed angles in a circle intercept arcs TWICE their measure
2 * (2x + 4x+24) = 360
x = 26
sooo EFC =4x +24 = 4*26 + 24 = 128 degrees
First one
Central angles EAJ and EKJ span the same arcs as their measure
So....angle EKJ will span an arc of 360 - 168 = 192°
Second one
This one is similar to the first
Since arc QRT =198°
Then arc QAT = angle QAT = 360 - 198 = 162°
Last one
Quadrilateral DEFC is a cyclic quadrilateral.....opposite angles will sum to 180°
So...The sum of angles EDC and EFC = 180°
So
2x + (4x + 24) = 180
6x + 24 = 180 subtract 24 from both sides
6x = 156 divide both sides by 6
x = 26
So...angle EFC = (4(26) + 24) = 128°