We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
139
3
avatar+256 

Two chords,  AB and CD  meet inside a circle at P. If AP=3 and CP=8 then what is BP over DP?

Thanks and if you can explain so I can do the next one that would be appreciated!

 Apr 12, 2019
 #1
avatar+52 
0

Multiply the section of the chord, they should be equal to each other.

 Apr 12, 2019
 #2
avatar+104648 
+1

We can use the intersecting chord theorem, here....

 

We have that 

 

AP * BP  =  CP * DP

 

3 * BP  =  8 *  DP          divide both sides by 3, DP

 

BP / DP  =  8 / 3

 

cool  cool cool 

 Apr 12, 2019
 #3
avatar+256 
+1

Thank you! 

 Apr 12, 2019

9 Online Users

avatar