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Two chords,  AB and CD  meet inside a circle at P. If AP=3 and CP=8 then what is BP over DP?

Thanks and if you can explain so I can do the next one that would be appreciated!

 Apr 12, 2019
 #1
avatar+52 
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Multiply the section of the chord, they should be equal to each other.

 Apr 12, 2019
 #2
avatar+106533 
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We can use the intersecting chord theorem, here....

 

We have that 

 

AP * BP  =  CP * DP

 

3 * BP  =  8 *  DP          divide both sides by 3, DP

 

BP / DP  =  8 / 3

 

cool  cool cool 

 Apr 12, 2019
 #3
avatar+256 
+1

Thank you! 

 Apr 12, 2019

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