I haven't really learned this stuff at school, but I can assume that if AB and CD are parallel and chord AC is 100, then chord BD must also be 100, so that makes the measure of angle BOD = 100°
Answer: 100°
Connect AC , AO
Angle CAB = 90 = angle ACB
So arc CDB = 180 = arc DCA
Then BC and AD are diameters
Angle ABC = (1/2) 100 = 50 = Angle ADC
ABODC is a pentagon....the sum of its interior angles = 540
So angle
BOD = 540 - 2(90) - 2(50) = 540 - 180 - 100 = 260
So angle BOD = 360 - 260 = 100 ( just as DS2011 found !!!