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0
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avatar+51 

Could you please help

melvsky  May 8, 2018
edited by melvsky  May 8, 2018
 #1
avatar+91148 
+2

 

 

15.

 

Since the  diameter is perpendicular to the chord AB,  then it bisescts  AB....thus.....AE  = BE  =  6

 

And the intersecting  chord theorem says this

 

DE * CE  = AE  * BE

 

DE  *  2  =   6 * 6

 

DE  * 2   = 36     divide both sides by 2

 

DE  = 18

 

So....the diameter  =  DE + CE  = 18  + 2   =  20

 

And the radius is  1/2 of this  = 10

 

 

cool cool cool

CPhill  May 8, 2018
edited by CPhill  May 8, 2018
 #2
avatar+91148 
+2

19....

 

Since  minor arc MN  = minor arc  QP......then the chords span  equal arcs......and, by Euclid, chords spanning equal arcs  are equidistant from the center of a circle

 

 

 

cool cool cool

CPhill  May 8, 2018
 #3
avatar+51 
+1

Thank you very much for all you have done. I still have more homwork so I will post more questions, I hope that's ok.

melvsky  May 8, 2018
 #4
avatar+91148 
0

OK...post away.......we'll see if we know any of the answers.....!!!!

 

 

 

cool cool cool

CPhill  May 8, 2018

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