I've already solved this problem, but I'd like a second opinion to make sure I got it correct.
The diameter of a circle is 3yd. I need to find the circumference and area.
My Answers:
Area: (approx.) 7.1yd^2
Circumference: (approx.) 9.4yd
D=3 yd
R=1.5 yd
$$Area=\pi R^2=\pi (1.5)^2$$
$${\left({\mathtt{1.5}}\right)}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{\pi}} = {\mathtt{7.068\: \!583\: \!470\: \!577\: \!034\: \!8}}$$
so 7.1 sq yds is correct
$$C = \pi D = 3 \pi$$
$${\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{\pi}} = {\mathtt{9.424\: \!777\: \!960\: \!769\: \!379\: \!7}}$$
and 9.4 yds is correct for the circumference
well done
D=3 yd
R=1.5 yd
$$Area=\pi R^2=\pi (1.5)^2$$
$${\left({\mathtt{1.5}}\right)}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{\pi}} = {\mathtt{7.068\: \!583\: \!470\: \!577\: \!034\: \!8}}$$
so 7.1 sq yds is correct
$$C = \pi D = 3 \pi$$
$${\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{\pi}} = {\mathtt{9.424\: \!777\: \!960\: \!769\: \!379\: \!7}}$$
and 9.4 yds is correct for the circumference
well done