If $3a + b + c = -3, a+3b+c = 9, a+b+3c = 19$, then find $abc$.
a = -5, b = 1, and c = 11, so abc = (-5)(1)(11) = -55.
Thanks for your effort but it wasn't right. Also only the a, b, and c values that you found only work with the first two equations but not a+b+3c=19 because -5+1+3(11)=29 and not 19.
