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If $3a + b + c = -3, a+3b+c = 9, a+b+3c = 19$, then find $abc$. 

 Mar 19, 2021
 #1
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a = -5, b = 1, and c = 11, so abc = (-5)(1)(11) = -55.

 Mar 19, 2021
 #2
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Thanks for your effort but it wasn't right. Also only the a, b, and c values that you found only work with the first two equations but not a+b+3c=19 because -5+1+3(11)=29 and not 19. 

 Mar 19, 2021

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