college algebra?

Well the problem e^2 would have to multiply correct..? And in order to get the answer you would have to do so, and from doing that getting the answer isn't going to be just a straight answer but in fact a decimal. But I'll be nice and give it out straight then rather you beg Haha I'm only teasing so here you go ! The answer to e^2=7.38

-Veronica

clk2013:

if ln e = 1, then ln e^2 = ?

I want you to look at at a different question first.
x = log ₂8
I can write this a different way
8 = 2 ^x
so x must be 3 because 2*2*2=2 ³=8

Remember, a logarithm (log) is a power (or exponent)

so if
x = log ₂(8 ⁴)
(8 ⁴) = 2 ^x
(2 ³) ⁴ = 2 ^x

2 ^(3*4) = 2 ^x

3*4 = x
x=12

Now lets see if we can do this more quickly.
We know that log ₂8 = 3
so
log ₂(8 ⁴) = 4 * log ₂8 = 4*3 = 12

the general rule is
log _b(x ^d) = d * log _bx

This is a page of logarithmic identities
http://en.wikipedia.org/wiki/List_of_logarithmic_identities ( you might like to bookmark this webpage )

also, your question tells you that lne=1 but you should really know this yourself
ln means log _e (log base e)
lets consider
y=log _ee
I can rearrange this to
e = e ^y
e ¹ = e ^y
y=1
that is why lne=1

You should be able to do your own question now.