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You roll 4 fair dice with the numbers 1, 2, 3, 4, 5, and 6. What is the probability that AT LEAST 2 dice roll a 3?

 

I want a thorough explanation pls!

 

Thx.

 Jan 8, 2023
 #1
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The probability is 16/27.

 Jan 8, 2023
 #2
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Could you provide an explanation?

The answer is something different.

Guest Jan 8, 2023
 #3
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The probability is:

 

[(4  nCr  2) * 5^2 + (4  nCr  3) * 5^1 + (4  nCr  0) * 5^0] ==171 / 6^4 ==19 / 144

 Jan 8, 2023

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