You roll 4 fair dice with the numbers 1, 2, 3, 4, 5, and 6. What is the probability that AT LEAST 2 dice roll a 3?
I want a thorough explanation pls!
Thx.
The probability is 16/27.
Could you provide an explanation?
The answer is something different.
The probability is:
[(4 nCr 2) * 5^2 + (4 nCr 3) * 5^1 + (4 nCr 0) * 5^0] ==171 / 6^4 ==19 / 144
