You roll 4 fair dice with the numbers 1, 2, 3, 4, 5, and 6. What is the probability that AT LEAST 2 dice roll a 3?

I want a thorough explanation pls!

Thx.

The probability is 16/27.

Could you provide an explanation?

The answer is something different.

The probability is:

[(4 nCr 2) * 5^2 + (4 nCr 3) * 5^1 + (4 nCr 0) * 5^0] ==171 / 6^4 ==19 / 144