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In how many ways can we choose 3 distinct letters of the alphabet, without regard to order, if we must choose 1 vowel (A, E, I, O, or U) and 2 consonants?

 Apr 26, 2018
 #1
avatar+98005 
+3

Since order is not a concern, we have 5 ways to pick a vowel....21 ways to pick one consonant.... and 20 ways to pick the second consonant...so....

 

5 * 21 * 20   =

 

2100 ways

 

 

cool cool cool

 Apr 26, 2018
edited by CPhill  Apr 26, 2018
 #3
avatar+290 
+2

Wait, I just realized... I got the same exact answer but the system said it was incorrect... Could you please look into the problem and see? Thanks again!

TheMathCoder  Apr 26, 2018
 #2
avatar+290 
+3

Thanks a lot CPhill!

 Apr 26, 2018

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