In how many ways can we choose 3 distinct letters of the alphabet, without regard to order, if we must choose 1 vowel (A, E, I, O, or U) and 2 consonants?
Since order is not a concern, we have 5 ways to pick a vowel....21 ways to pick one consonant.... and 20 ways to pick the second consonant...so....
5 * 21 * 20 =
2100 ways
Wait, I just realized... I got the same exact answer but the system said it was incorrect... Could you please look into the problem and see? Thanks again!