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# cometh h're, englut mine own coxcomb, and solveth thy problemth

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I have a bag with yellow and blue marbles in it. At the moment, the ratio of blue marbles to yellow marbles is 4:3. If I add 5 blue marbles and remove 3 yellow marbles, the ratio will be 7:3. How many blue marbles were in the bag before I added more?

Grant you mercy if 't be true thee solveth this

Apr 6, 2020

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I get 16 blue marbles.

Hope it helps!

Apr 6, 2020
#2
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Thanketh thee.

Apr 6, 2020
#3
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I giveth thy welcometh. HELPMEEEEEEEEEEEEE  Apr 6, 2020
#4
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Let  the number  of  original yellow marbles  =  Y

Let the number  of original blue  marbles  be = B

And we know  that    B/Y  = 4/3  ⇒  B = (4/3)Y  ⇒  Y = (3/4)B

And  we  have  that

B + 5           7

_____  =   ___

Y - 3           3

Subbing  for  Y  we  have that

B + 5                     7

_________  =     ___     cross-multiply

(3/4)B - 3              3

3(B + 5)  = 7 [ (3/4)B - 3 ]      simplify

3B + 15 = (21/4)B - 21      add 21 to both sidws, subtract 3B from both sides

36    =  (21/4 - 3)B

36  = ( 21/4 - 12/4) B

36  = (9/4)B      multiply both sides  by 4/9

16  = B  =  original number of  blue marbles   Apr 6, 2020