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avatar+243 

I have a bag with yellow and blue marbles in it. At the moment, the ratio of blue marbles to yellow marbles is 4:3. If I add 5 blue marbles and remove 3 yellow marbles, the ratio will be 7:3. How many blue marbles were in the bag before I added more?

 

Grant you mercy if 't be true thee solveth this

 Apr 6, 2020
 #1
avatar+932 
+2

I get 16 blue marbles.

 

Hope it helps!

 Apr 6, 2020
 #2
avatar+243 
+1

Thanketh thee.

 Apr 6, 2020
 #3
avatar+932 
+1

I giveth thy welcometh. laugh

HELPMEEEEEEEEEEEEE  Apr 6, 2020
 #4
avatar+111329 
+1

Let  the number  of  original yellow marbles  =  Y

 

Let the number  of original blue  marbles  be = B

 

And we know  that    B/Y  = 4/3  ⇒  B = (4/3)Y  ⇒  Y = (3/4)B

 

And  we  have  that

 

B + 5           7

_____  =   ___  

Y - 3           3

 

Subbing  for  Y  we  have that

 

B + 5                     7

_________  =     ___     cross-multiply

(3/4)B - 3              3

 

 

3(B + 5)  = 7 [ (3/4)B - 3 ]      simplify

 

3B + 15 = (21/4)B - 21      add 21 to both sidws, subtract 3B from both sides

 

36    =  (21/4 - 3)B

 

36  = ( 21/4 - 12/4) B

 

36  = (9/4)B      multiply both sides  by 4/9

 

16  = B  =  original number of  blue marbles

 

 

cool cool cool

 Apr 6, 2020

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