after 2 years the population was 20500 and after 4 years the population 184500. What is the common ratio of the growing population?
The population of the town grew from 2,278 @ 200% per year until the population hit 20,500 in two years. And further 2 years' growth @ 200% the population hit 184,500.
The common ratio of the growing population is 200%.
AM I missing part of the question here??? Where does it say what the original pop was before the 2 year measurement???
20500 (x^4) = 184500
x^4 = 184500/20500
x = 1.73205 or 173% per year
20500/1.73205^2 = 6833 population originally in two years at 173% growth annually it will be
6833 x 1.73205 x 1.73205 = 20500
~jc (not sure about this one)
+129847 184500 = 20500 (1 + r)^2 divide both sides by 20500
9 = (1 + r)^2 take the log of both sides
log(9) = 2log (1 + r)
log(9)/2 = log(1 + r) and this says that
10^[log(9)/2] = 1 + r
r = 10^[log(9)/2] - 1 = about 3 - 1 = 2 = 200%
AM I missing part of the question here??? Where does it say what the original pop was before the 2 year measurement???
20500 (x^4) = 184500
x^4 = 184500/20500
x = 1.73205 or 173% per year
20500/1.73205^2 = 6833 population originally in two years at 173% growth annually it will be
6833 x 1.73205 x 1.73205 = 20500
~jc (not sure about this one)
Yah, CPhil got this one...I misread the question....I thought it was 4 years from 20500 to 184500...it was only 2...AND I used the wrong equation...d'oh!
Way to go Chris!!
