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Find all real numbers x and y such that

 

\(x^2y^2+x^2+y^2+2xy=40\) and \(xy + x+y=8\)

 

Please explain your answer!

 Dec 22, 2020
 #1
avatar+114818 
+1

Hint:

 

\(x^2+y^2+2xy=(x+y)^2\\ and\\ x+y=8-xy\)

 

After I continued on a little further I found it easier to substitute z=xy and solve for z

then I solved for x and y after that.

 Dec 22, 2020

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