h(x)=−2x^(2)+4x+16,
What is the height of the ball at the time it is thrown?
answer:blank meters
I will assume 'x' is the time when the ball is thrown x = 0
Put that value of 'x' in to the equation to calculate initial height......
so your saying the answer is zero
C'mon..... you put x= 0 into the equation and got 0 ???
the answer wasnt zero im depressed
Re-compute: -2 (0)^2 + 4(0) +16 = ...........
What is the height of the ball at the time it is thrown
+36915 
