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0
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h(x)=−2x^(2)+4x+16,

What is the height of the ball at the time it is thrown?

answer:blank meters

 Apr 28, 2020
 #1
avatar+26004 
+1

I will assume   'x' is the time      when the ball is thrown  x = 0    

Put that value of 'x' in to the equation to calculate initial height......

 Apr 28, 2020
 #2
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0

so your saying the answer is zero

Guest Apr 28, 2020
 #3
avatar+26004 
0

C'mon..... you put   x= 0 into the equation and got  0 ???

ElectricPavlov  Apr 28, 2020
 #4
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0

the answer wasnt zero im depressed

Guest Apr 28, 2020
 #5
avatar+26004 
+1

Re-compute:    -2 (0)^2  + 4(0)  +16 = ...........

ElectricPavlov  Apr 28, 2020
 #6
avatar+12300 
+2

h(x)=−2x^(2)+4x+16,

What is the height of the ball at the time it is thrown

 

laugh

 Apr 28, 2020

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