The radius r of a circle inscribed within three mutually externally tangent circles of radii a, b, and c is given by
1r=1a+1b+1c+2√1ab+1ac+1bc.What is the value of r when a=4, b=9 and c=36?
1/r = 1/4 + 1/9 + 1/36 + 2sqrt [ 1/36 + 1/144 + 1/324 ]
1/r = 14/36 + 2sqrt [49/1296]
1/r = 14/36 + 2 (7/36)
1/r = 14/36 + 14/36
1/r = 7/9
r = 9/7