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The radius r  of a circle inscribed within three mutually externally tangent circles of radii ab, and c is given by

1r=1a+1b+1c+21ab+1ac+1bc.
What is the value of  r when a=4b=9 and c=36?


 

 Dec 29, 2023
 #1
avatar+130466 
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1/r =  1/4 + 1/9 + 1/36 + 2sqrt [ 1/36 + 1/144 + 1/324 ]

 

1/r =  14/36  + 2sqrt [49/1296]

 

1/r = 14/36 + 2 (7/36)

 

1/r  = 14/36 + 14/36

 

1/r = 7/9

 

r = 9/7

 

cool cool cool

 Dec 29, 2023

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