Let z and w be complex numbers such that |z| = |w| = 1 and zw is not equal to -1.

(a) Prove that conjugate {z} = 1/z and conjugate{w} = 1/w

(b) Prove that ={z + w}/{zw + 1} is a real number.

Maurya Jul 15, 2024

#1**0 **

(a) Let w = a + bi and z = c + di. The rest is expanding.

(b) Let w = a + bi and z = c + di. Then

\[\dfrac{w + z}{1 + wz} = \dfrac{a + c + bi + di}{1 + (a + bi)(c + di)}\]

To express this in rectangular form, we can multiply the numerator and denominator by the conjugate:

\[\dfrac{a + c + bi + di}{1 + (a + bi)(c + di)} = \dfrac{(a + c + bi + di)((1 - (a + bi)(c + di))}{(1 + (a + bi)(c + di))(1 - (a + bi)(c + di))}\]

The denominator simplifies to (1 - (a^2 + b^2)(c^2 + d^2)), which is real. The numerator simplifies to a^2 - b^2 + c^2 - d^2, which is also real. Therefore, the complex number (z + w)/(zw + 1) is real.

LiIIiam0216 Jul 15, 2024