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Simplify (1-i)/(2+3i-3+i), where i^2 = -1.

 Jan 28, 2022
 #1
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Simplified to:

\(-i + 1\over4i - 1\)

 

Simplified with the difference of squares:

\((-i + 1)(4i + 1)\over(4i)^2 - 1\)

Simplified to:

\(-4i^2 + 4i - i + 1\over16i^2 - 1\)

 

Substituted to:

\(3i + 5\over-17\)

 

Thus, the expression is simplified to:

\(3i + 5\over-17\)

 

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 Jan 28, 2022

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