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Find all complex numbers z that satisfy z^2 = i/2.

 Feb 3, 2022
 #1
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Put the number into polar form (1/2,π/2),  (abbreviated).

We're finding a root so the number has to be put into its multivalued form, (1/2,π/2+2kπ),k=0,1,2,...

z=(1/2,π/2+2kπ)1/2,k=0,1,=(1/2,π/4+kπ),k=0,1,=(k=0),(1/2,π/4)=(1/2+i/2),or (k=1),(1/2,5π/4)=(1/2i/2).

 Feb 4, 2022

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