Put the number into polar form (1/2,π/2), (abbreviated).
We're finding a root so the number has to be put into its multivalued form, (1/2,π/2+2kπ),k=0,1,2,...
z=(1/2,π/2+2kπ)1/2,k=0,1,=(1/√2,π/4+kπ),k=0,1,=(k=0),(1/√2,π/4)=(1/2+i/2),or (k=1),(1/√2,5π/4)=(−1/2−i/2).