+51 \(QED = (11-5i)(3-2i)(2i)\)
We can split this up into two parts. Let's first compute \((11-5i)(3-2i)\), and then multiply it again by \(2i\).
\((11-5i)(3-2i) = 11(3-2i)-5i(3-2i) = 33-22i-15i+10i^2 = 33-37i-10 = 23-37i.\)
\(2i\cdot(23-37i) = 46i-74i^2 = \boxed{74+46i}\)
